A particle of mass m and charge q is in an electric and magnetic field given by E-2-3- B-4-6k- The charged particle is shifted from the origin to the point Px-1- y-1 along a straight path- The magnitude of the total work done is-

The correct option is D 5 q F⃗_⃗n⃗e⃗t⃗=qE⃗+q(v⃗×B⃗) =(2qî+3qĵ)+q(v⃗×B⃗) W=F⃗_⃗n⃗e⃗t⃗·S⃗ =2q+3q =5q . ...

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Byju's Answer

Standard XII

Physics

Analysis of Force Equation

A particle of...

Question

A particle of mass m and charge q is in an electric and magnetic field given by $\to E = 2^i + 3^j$ ; $\to B = 4^j + 6^k$ . The charged particle is shifted from the origin to the point $P (x = 1; y = 1)$ along a straight path. The magnitude of the total work done is?

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Solution

The correct option is D $5$ q
$_{n e t} = q \to E + q (\to v \times \to B)$
$= (2 q^i + 3 q^j) + q (\to v \times \to B)$
$W =_{n e t} \cdot \to S$
$= 2 q + 3 q$
$= 5 q$ .

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A particle of mass m and charge q is in an electric and magnetic field given by →E=2^i+3^j; →B=4^j+6^k. The charged particle is shifted from the origin to the point P(x=1;y=1) along a straight path. The magnitude of the total work done is?

The correct option is D 5q→Fnet=q→E+q(→v×→B)=(2q^i+3q^j)+q(→v×→B)W=→Fnet⋅→S=2q+3q=5q.

A particle of mass m and charge q is in an electric and magnetic field given by $\to E = 2^i + 3^j$ ; $\to B = 4^j + 6^k$ . The charged particle is shifted from the origin to the point $P (x = 1; y = 1)$ along a straight path. The magnitude of the total work done is?

The correct option is D $5$ q
$_{n e t} = q \to E + q (\to v \times \to B)$
$= (2 q^i + 3 q^j) + q (\to v \times \to B)$
$W =_{n e t} \cdot \to S$
$= 2 q + 3 q$
$= 5 q$ .