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Question

A particle of mass $$m$$ and charge $$q$$ is placed at rest in a uniform electric field $$E$$ and then released. The kinetic energy attained by the particle after moving a distance $$y$$ is :



A
qEy2
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B
qE2y
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C
qEy
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D
q2Ey
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Solution

The correct option is B $$qEy$$
According to work-energy theorem:
Kinetic energy attained by the particle is equal to work done on the particle by electric field
$$\therefore K.E.=(q E)y$$

Physics
NCERT
Standard XII

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