A particle of mass m and charge q is placed at rest in a uniform electric field E and then released. The kinetic energy attained by the particle after moving a distance y is :
A
qEy2
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B
qE2y
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C
qEy
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D
q2Ey
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Solution
The correct option is BqEy
According to work-energy theorem:
Kinetic energy attained by the particle is equal to work done on the particle by electric field ∴K.E.=(qE)y