A particle of mass m and charge q is placed at rest in uniform electric field E and then released. The kinetic energy gained by the particle after a distance y is
A
12qEy
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B
qEy
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C
4qEy
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D
2qEy
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Solution
The correct option is BqEy Initially kinetic energy Ki=0J
After releasing of charged particle, the kinetic energy is changed. Lets say final kinetic energy is Kf.
Work energy theorem states that ΔK=W
Therefore Kf−Ki=F×y
Since F=qE