A particle of mass m and charge Q is placed in an electric field of intensity E, which varies with time t as E=E0sinωt. It will undergo simple harmonic motion of amplitude
A
QE20mω2
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B
QE0mω2
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C
√QE0mω2
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D
QE0mω
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Solution
The correct option is BQE0mω2 Force on charge =QE=QE0sinωt
acceleration =QE0msinωt...(1)
magnituide of acceleration of particle in SHM is a=|Aω2sinωt|...(2)
compare equation (1) and (2) Aω2=QE0m⇒A=QE0mω2.