wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle of mass m and charge q, moving with velocity V enters Region II normal to the boundary as shown in the figure. Region II has a uniform magnetic field B perpendicular to the plane of the paper. The length of the Region II is Choose the correct choice(s).
32276.PNG

A
The particle enters Region III only if its velocity V>qBm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
The particle enters Region III only if its velocity V<qBm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Path length of the particle in Region II is maximum when velocity V=qBm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Time spent in Region II is same for any velocity V as long as the particle returns to Region I
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A The particle enters Region III only if its velocity V>qBm
B Path length of the particle in Region II is maximum when velocity V=qBm
C Time spent in Region II is same for any velocity V as long as the particle returns to Region I
Path of the particle in region II is circular.
If the width l of region II is less than the radius(r=mvqB) of the circle, the particle will enter region C( i.e l<mvqB i.e v>qlBm )
If v=qlBm, particle will have max path length in region II.
If the particle returns to region I, time spent inside region II is 12 of T=2πmqB which is independent of v.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Charge Motion in a Magnetic Field
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon