A particle of mass m begins to slide down a fixed smooth sphere from the top with negligible initial velocity. What is its tangential acceleration when it breaks off the sphere?
A
2g3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
√5g3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
g3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B√5g3
If a particle starts from the top,the speed of the particle will be given by energy conservation law.It is given as
change in the potential energy = gain in kinetic energy
mgR(1−cosθ)=12mv2
from force equation now
since it break off at this position so normal force will be zero
mgcosθ=mv2R
now we will use the value from above two equations