Question

A particle of mass $m$ describes a circle of radius $\left(r\right)$. The centripetal acceleration of the particle is $\frac{4m}{r^2}$. The momentum of the particle:

• A. $\frac{2m}{r}$
• B. $\frac{2{\sqrt{m}}^3}{\sqrt{r}}$
• C. $\frac{4m}{r}$
• D. $\frac{4m}{\sqrt{r}}$

Answer 1

The correct option is B $\frac{2{\sqrt{m}}^3}{\sqrt{r}}$

$\frac{v^2}{r}=\frac{4m}{r^2}{v}^2=\frac{4m}{r^2}rmomentum=mv=m\times \sqrt{\frac{4m}{r}}=2\sqrt{\frac{m^3}{r}}$