CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Helical Motion

A particle of...

Question

A particle of mass m having a charge q enters into a circular region of radius R with velocity v directed towards the centre.The strength of magnetic field is B.Find the deviation in the path of the particle.

Open in App

Solution

$θ = {t a n}^{- 1} (\frac{R}{r}) = {t a n}^{- 1} (\frac{R}{m v / B q})$
Deviation $= 2 θ = 2 {t a n}^{- 1} (\frac{B q R}{m v})$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A particle of mass m having a charge q enters into a circular region of radius R with velocity v directed towards the centre. The strength of magnetic field is B. Find the deviation in the path of the particle.

Q. A charged particle of mass m and charge

q

is accelerated through a potential difference of

V

volts.It enters a region of uniform magnetic field

B

which is directed perpendicular to the direction of motion of the particle.The particle will move on a circular path of radius

Q. A particle having charge 6C enters perpendicularly in a uniform magnetic field of strength 100T with a momentum of
36kg m/s. The radius of the circular path of the particle is

[T a k e μ_{0} = 4 \times 10^{- 7} T m / A]

Q. A charged particle of mass

m

q

is accelerated through a potential difference of

V

. It enters a region of uniform magnetic field

B

, which is directed perpendicular to the direction of motion of the particle. The particle will move on a circular path of radius given by -

Q. A particle of mass in and charge Q moving with velocity v enters a region of uniform magnetic field of induction B. Its path in the region is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Charge Motion in a Magnetic Field

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon