Question

A particle of mass $m$ is attached to a rod of length $I$, and it rotates in a circle with a constant angular velocity $\omega$. An observer $P$ is rigidly fixed on the rod at a distance $L/2$ from the centre. The acceleration of $m$ and the pseduo force on $m$ from the frame of reference of $P$ must be respectively

• A. $zero,zero$
• B. $zero,m{\omega }^2\frac{L}{2}$
• C. ${\omega }^2\frac{L}{2},m{\omega }^2\frac{L}{2}$
• D. $zero,m{\omega }^{2}L$

Answer 1

The correct option is A $zero,zero$

$\begin{array}{c}\text{Correct option is}\left(A\right)\\ \text{As we know rod is rotating with constant}\\ \text{w so, no tangencial accerleration.}\\ \text{But with respect to frame}P\text{;}\\ \text{Centripetal acceleration also becomes zero}\\ \text{as it is also same position of that of}\\ \text{mass.}\end{array}$