A particle of mass m is describing a circular path of radius r with uniform speed. If L is the angular momentum of the particle (about the axis of the clock) then the kinetic energy of the particle is
A
L2mr2
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B
mr2L
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C
L22mr2
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D
L2r2m
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Solution
The correct option is CL22mr2
Kinetic energy K.E.=12Iw2
We know that w=LI
⟹K.E.=L22I
Now, moment of inertial of a particle moving in circular path of radius r, I=mr2