wiz-icon
MyQuestionIcon
MyQuestionIcon
5
You visited us 5 times! Enjoying our articles? Unlock Full Access!
Question

A particle of mass m is executing oscillations about the origin on the x-axis. Its potential energy is V(x)=k|x|3, where k is a positive constant. If the amplitude of oscillation is a, then its time period T is

A
Proportional to
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Independent of a
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Proportional to
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Proportional to
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Proportional to
V=k|x|3F=dvdx=3k|x|2 ........(1)
The equation of simple harmonic motion is given as
x=asinωtmd2xdt2=m(aω2sinωt)=mω2x ..........(2)
Using (i) and (ii), we obtain3k|x|2=mω2xω=3kxmT=2πm3kxT=2πm3kasinωtT1a


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Energy in SHM
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon