A particle of mass $m$ is fixed to one end of a light rigid rod of length $l$ and rotated in a vertical circular path about its other end. The minimum speed of the particle at its highest point must be:

Zero

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\sqrt{g l}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{1.5 g l}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{2 g l}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Zero
Unlike a rope or string, the light rod cannot slack during rotation, hence the particle is able to reach the topmost point of the circle with zero velocity.
Its velocity becomes zero at the topmost point, but due to its inertia, it will fall in forward direction and complete the circle.

Suggest Corrections

Similar questions

Q. A particle of mass

m

is fixed to one end of a light rigid rod of length

l

and rotated in a vertical circular path about its other end. The minimum speed of the particle at its highest point must be

Q. A particle of mass m is tied to a light string of length l and rotated along a vertical circular path. What should be the minimum speed at a highest point of its path so that the string does not become slack at any position?

Two particles of mass 'm' each are attached to a light rod of length 'd', one at its centre and the other at a free end. The rod is fixed at the other end and is rotated in a plane at an angular speed $ω$ . Calculate the angular momentum of the particle at the end with respect to the particle at the centre.

Q. A particle is attached to the lower end of a uniform rod which is hinged at its other end as shown in the figure. Them minimum speed is given to the particles so that the rod performs a circular motion in a vertical plane will be :
[ length of the rod is l, consider masses of both rod and particle to be the same]