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Standard X

Physics

Impulse

A particle of...

Question

A particle of mass $m$ is moving a uniform velocity $v_{1}$ . It is given an impulse such that its velocity becomes $v_{2}$ . The impulse is equal to

m [| v_{2} | - | v_{1} |]

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1 / 2 m [v_{1}^{2} - v_{1}^{2}]

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m [v_{1} + v_{2}]

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m [v_{2} - v_{1}]

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Solution

The correct option is D $m [v_{2} - v_{1}]$
The impulse is equal to $m [v_{2} - v_{1}]$ .
Option $D$ is correct answer.

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A particle of mass m is moving a uniform velocity v1. It is given an impulse such that its velocity becomes v2. The impulse is equal to

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The correct option is D $m [v_{2} - v_{1}]$
The impulse is equal to $m [v_{2} - v_{1}]$ .
Option $D$ is correct answer.