CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration ac varies with time t as ac=k2rt2, where k is a constant. The power delivered to the particles by the force acting on it is

A
2πmk2r2t
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
mk2r2t
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
mk4r2t53
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B mk2r2t
The centrifugal force mv2r
Centripetal force
mv2r=m.k2.rt2V=krt
Tangential accelration =dvdt=kr
Power delivered =Force×Velocity=mkr×Krt=mK2r2t

1117985_986773_ans_806ab426a9194750a8d61c42b7051b1e.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon