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Question

A particle of mass m is moving in a horizontal circle of radius r under a centripetal force equal to Kr2 , where K is a constant. The total energy of the particle is 



Solution

The correct option is B


Here mv2r=Kr2K.E=12mv2=K2r

U=rF.dr=r(Kr2)dr=kr

Total energy E=K.E+P.E=K2rKr=K2r

 

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