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Kinetic Energy

A particle of...

Question

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to $(- k / r^{2})$ , where k is a constant. The total energy of the particle is?

A

k / 2 r

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B

- k / 2 r

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C

kr

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D

- k / r

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Solution

The correct option is A $- k / 2 r$
For kinetic energy $m ν^{2} / r$
$= k / r^{2}$
$= K E = k / 2 r$
$E = K E + U$
$E = - k / 2 r$

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