CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle of mass m is moving in the space under the influence of a force ¯F=¯VׯA where ¯V is the velocity of particle and A is constant vector given as A=A^k . At t = 0, particle is at origin and moving with initial V0=v1^i+v2^k. Choose the CORRECT statement(s).

A
The magnitude of linear momentum of the particle is constant
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Velocity of particle at any time t is v1cos(Amt)^iv1sin(Amt)^j+v2^k
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Particle will perform motion on helical path with constant pitch
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Magnitude of angular velocity of the particle is variable
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A The magnitude of linear momentum of the particle is constant
B Velocity of particle at any time t is v1cos(Amt)^iv1sin(Amt)^j+v2^k
C Particle will perform motion on helical path with constant pitch

F=(v1^i+v2^k)×(A^k)=Av(^j)

mv2R=AvR=mvAω=Am

v=v1cosθ^iv1sinθ^j+v2^k

v=v1cos(Amt)^iv1sin(Amt)^j+v2^k


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circular Motion: A Need for Speed
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon