Question

A particle of mass m is moving with a uniform speed v in x-y plane along a straight line, y = x + k, the angular momentum of the particle about the origin is

• A.
• B.
• C.
• D. mvk

Answer 1

The correct option is A

$y=mx+candy=x+k\Rightarrow \theta ={45}^{\circ }andc=k\therefore \text{Angular momentum},L=mvmv\times k\times \frac{1}{\sqrt{2}}=\frac{mvk}{\sqrt{2}}$