A particle of mass m is moving with constant velocity v parallel to x-axis in x-y plane as shown in figure. Calculate its angular momentum with respect to origin at anyinstant 't'.

mrv

No worries! We‘ve got your back. Try BYJU‘S free classes today!

mvb

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

mvb

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2mvb

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
mvb

$\to L = \to r x \to p$
$= (r sin θ) p$
$= m v b$

Suggest Corrections

Similar questions

A particle of mass $m$ is moving with constant velocity $v$ parallel to $x$ -axis in $x - y$ plane as shown in figure. Calculate its angular momentum with respect to origin at anyinstant ' $t$ '.

Q. A particle of mass

m

is moving with constant velocity

v

parallel to the x-axis in

x - y

plane as shown in the figure. Calculate its angular momentum with respect to the origin at any time

t

Q. If a particle of mass m is moving with constant velocity v parallel to x-axis in x-y plane as shown in fig. Its angular momentum with respect to origin at any time t will be

Q. If a particle of mass m is moving with constant velocity

V

parallel to

X -

axis in

X Y

plane at a distance

y

. Then its angular momentum at any time

^{'} t^{'}

with respect to the origin is :

Join BYJU'S Learning Program

A particle of mass m is moving with constant velocity v parallel to x-axis in x-y plane as shown in figure. Calculate its angular momentum with respect to origin at anyinstant 't'.

The correct option is B mvb →L=→rx→p =(rsinθ)p =mvb

The correct option is B
mvb

$\to L = \to r x \to p$
$= (r sin θ) p$
$= m v b$