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Standard XII

Physics

Angular Momentum

A particle of...

Question

A particle of mass m is moving with constant velocity v parallel to x-axis in x-y plane as shown in figure. Calculate its angular momentum with respect to origin at anyinstant 't'.

mrv

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mvb

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mvb

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2mvb

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Solution

The correct option is B
mvb

$\to L = \to r x \to p$
$= (r sin θ) p$
$= m v b$

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A particle of mass m is moving with constant velocity v parallel to x-axis in x-y plane as shown in figure. Calculate its angular momentum with respect to origin at anyinstant 't'.

The correct option is B mvb →L=→rx→p =(rsinθ)p =mvb

The correct option is B
mvb

$\to L = \to r x \to p$
$= (r sin θ) p$
$= m v b$