A particle of mass m is moving with constant velocity →v on smooth horizontal surface. A constant force →F starts acting on particle perpendicular to velocity v. Radius of curvature after force F start acting is
A
mv2F
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B
mv2Fcosθ
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C
mv2Fsinθ
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D
None of these
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Solution
The correct option is Amv2F As we know that in circular motion force will always act perpendicular to velocity after that a body can maintain circular motion.Direction of velocity will act tangentially and force will act away from center. So F = mv2r r=mv2F