Question

A particle of mass $m$ is moving with constant velocity $\overrightarrow{v}$ on smooth horizontal surface. A constant force $\overrightarrow{F}$ starts acting on particle perpendicular to velocity $v$. Radius of curvature after force $F$ start acting is

• A. $\frac{m{v}^2}{F}$
• B. $\frac{m{v}^2}{Fcos\theta }$
• C. $\frac{m{v}^2}{Fsin\theta }$
• D. None of these

Answer 1

The correct option is A $\frac{m{v}^2}{F}$

As we know that in circular motion force will always act perpendicular to velocity after that a body can maintain circular motion.Direction of velocity will act tangentially and force will act away from center.
So F = $\frac{m{v}^2}{r}$
r=$\frac{m{v}^2}{F}$