wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle of mass ′m′ is moving with speed 8 m/s on a frictionless surface as shown in figure. If m<<M, then for one dimensional elastic collision, the speed of the lighter particle after collision will be


A
4 m/s in original direction
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4 m/s opposite to the original direction
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6 m/s in original direction
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6 m/s opposite to the original direction.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 4 m/s opposite to the original direction
Given, u1=8 m/s;u2=2 m/s
In the case of elastic collision, when m1<<m2
Speed of lighter particle (v1)=(m1m2m1+m2)u1+2m2u2m1+m2
=u1+2u2
Here, m<<M
v1=8+2(2)=4 m/s
(-ve sign indicates velocity is opposite to original direction)

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
A No-Loss Collision
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon