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Question

A particle of mass m is projected from the surface of earth with velocity v0 at angle Θ with horizontal. Suppose h be the maximum height of particle from surface of earth and v its speed at that point then v is.

A
v0cosθ
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B
>v0cosθ
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C
<v0cosθ
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D
zero
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Solution

The correct option is D <v0cosθ
Velocity perpendicular to the radial direction initially=v0cosθ
Final velocity is v perpendicular to the radial direction.
From conservation of angular momentum,
m(v0cosθ)R=mvr
v=Rrv0cosθ
Since r>Rv<v0cosθ

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