A particle of mass m is projected with velocity v making an angle of 45∘ with the horizontal. Themagnitude of the angular momentum of the particle about the point of projection when the particle is at its maximum height is (where g = acceleration due to gravity)
mv3(4√2g)
L=m u3 cosθ sin2 θ2g=mv3(4√2g) [As θ=45∘]