A particle of mass m is tied to the end of a string passing through a hollow tube on a circular table- The particle is revolved with angular velocity - The force required to be applied at the lower end of the string in order to maintain a dynamic equilibrium will be

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Standard XII

Physics

Measuring Mass

A particle of...

Question

A particle of mass $m$ is tied to the end of a string passing through a hollow tube on a circular table. The particle is revolved with angular velocity $ω$ . The force required to be applied at the lower end of the string in order to maintain a dynamic equilibrium will be

m ω^{2} r

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m g

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\frac{m ω^{2} r}{2}

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m ω^{2} r + m g

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Solution

The correct option is A $m ω^{2} r$
There is no gravitational force acting in the horizontal direction. Only the centripetal force acts and to maintain a dynamic equilibrium a force equal to centripetal force $m ω^{2} r$ acts.

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A particle of mass m is tied to the end of a string passing through a hollow tube on a circular table. The particle is revolved with angular velocity ω. The force required to be applied at the lower end of the string in order to maintain a dynamic equilibrium will be

The correct option is A mω2rThere is no gravitational force acting in the horizontal direction. Only the centripetal force acts and to maintain a dynamic equilibrium a force equal to centripetal force mω2r acts.

A particle of mass $m$ is tied to the end of a string passing through a hollow tube on a circular table. The particle is revolved with angular velocity $ω$ . The force required to be applied at the lower end of the string in order to maintain a dynamic equilibrium will be

The correct option is A $m ω^{2} r$
There is no gravitational force acting in the horizontal direction. Only the centripetal force acts and to maintain a dynamic equilibrium a force equal to centripetal force $m ω^{2} r$ acts.