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Angular Velocity

A particle of...

Question

A particle of mass $m$ move along a curve $y = x^{2}$ . When particle has $X -$ co-ordination as $1 / 2 m$ and $x -$ component of velocity as $4 m / s$ then.

the position coordinate of particle are

(1 / 2, 1 / 4) m

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the velocity of particle will be along the line

4 x - 4 y - 1 = 0

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the magnitude of velocity at that instant is

4 \sqrt{2} m / s

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the magnitude of angular momentum of particle about origin at that position is

0

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Solution

The correct options are
A the position coordinate of particle are $(1 / 2, 1 / 4) m$
B the velocity of particle will be along the line $4 x - 4 y - 1 = 0$ .
C the magnitude of velocity at that instant is $4 \sqrt{2} m / s$
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A particle of mass m move along a curve y=x2. When particle has X−co-ordination as 1/2m and x−component of velocity as 4m/s then.

The correct options are A the position coordinate of particle are (1/2,1/4)m B the velocity of particle will be along the line 4x−4y−1=0. C the magnitude of velocity at that instant is 4 √2 m/sundefined

A particle of mass $m$ move along a curve $y = x^{2}$ . When particle has $X -$ co-ordination as $1 / 2 m$ and $x -$ component of velocity as $4 m / s$ then.

The correct options are
A the position coordinate of particle are $(1 / 2, 1 / 4) m$
B the velocity of particle will be along the line $4 x - 4 y - 1 = 0$ .
C the magnitude of velocity at that instant is $4 \sqrt{2} m / s$
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