A particle of mass M moves with constant speed along a circular path of radius r under the action of a force F. Its speed is

\sqrt{\frac{r F}{m}}

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\sqrt{\frac{F}{r}}

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\sqrt{F m r}

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\sqrt{\frac{F}{m r}}

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Solution

The correct option is A $\sqrt{\frac{r F}{m}}$
$\begin{matrix} F = m v^{2} \Rightarrow V = \sqrt{\frac{F r}{m}} H e n c e, o p t i o n A i s c o r r e c t a n s w e r . \end{matrix}$

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