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Momentum

A particle of...

Question

A particle of mass m moving towards East with a velocity v collides with another particle of same mass moving towards North with the same speed and adheres to it. The velocity of the combined particle is

A

v / \sqrt{2}

along North-East

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B

v / \sqrt{5}

along North-East

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C

\sqrt{2} v

along North-East

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D

\sqrt{v}

along North-West

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Solution

The correct option is A $v / \sqrt{2}$ along North-East
Applying COLM
$m v^i + m v^j = 2 m {\to v}^{'}$
${\to v}^{'} = \frac{1}{2} (v^i + v^j) \Rightarrow v^{'} = \frac{v}{\sqrt{2}}$ along $N - E$

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