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Standard XII

Physics

Impulsive Forces in Collision

A particle of...

Question

A particle of mass m moving with velocity u makes an elastic one dimensional collision with a stationary particle of mass m. They are in contact for a very brief time T. Their force of interaction increases from zero to $F_{0}$ linearly in time $\frac{1}{2} T$ . The magnitude of $F_{0}$ is

\frac{m u}{T}

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\frac{2 m u}{T}

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\frac{m u}{2 T}

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\frac{3 m u}{T}

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Solution

The correct option is B $\frac{2 m u}{T}$
Impulse $=$ change in Momentum

$F_{0} \frac{T}{2} = m u$

$F_{0} = \frac{2 m u}{T}$

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A particle of mass m moving with velocity u makes an elastic one dimensional collision with a stationary particle of mass m. They are in contact for a very brief time T. Their force of interaction increases from zero to F0 linearly in time 12T. The magnitude of F0 is

The correct option is B 2muTImpulse = change in Momentum F0T2=muF0=2muT

A particle of mass m moving with velocity u makes an elastic one dimensional collision with a stationary particle of mass m. They are in contact for a very brief time T. Their force of interaction increases from zero to $F_{0}$ linearly in time $\frac{1}{2} T$ . The magnitude of $F_{0}$ is

The correct option is B $\frac{2 m u}{T}$
Impulse $=$ change in Momentum

$F_{0} \frac{T}{2} = m u$

$F_{0} = \frac{2 m u}{T}$