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Conservation of Momentum

A particle of...

Question

A particle of mass m moving with velocity v collides with a stationary particle of mass 2 m. They both join and move together after the collision. Then the speed of the system after collision is :

A

2 v

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B

\frac{v}{2}

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C

3 v

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D

\frac{v}{3}

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Solution

The correct option is B $\frac{v}{3}$
Applying conservation of momentum,
$m v + 0 = (2 m + m) v^{'} = 3 m v^{'}$
$v^{'} = \frac{m v}{3 m} = \frac{v}{3}$

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