A particle of mass $m$ moving with velocity $v$ strikes a stationary particle of mass $2 m$ and sticks to it. The speed of the system will be

v / 2

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2 v

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v / 3

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3 v

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Solution

The correct option is B $v / 3$
Since There is no external force, we can apply momentum conservation,
Initial momentum of the system = $m_{1} v_{1} + m_{2} v_{2}$
$P_{i} = m \times v - 2 m \times 0 = m v$
As body sticks together $∴$ final momentum = $(m_{1} + m_{2}) V$
By conservation of momentum $(m_{1} + m_{2}) V = P_{i}$
$(2 m + 1 m) \times V = m v$

$V = \frac{v}{3} m / s$

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