A particle of mass M, starting from rest, undergoes uniform acceleration. If the speed acquired in time T is V, the average power delivered to the particle is
A
MV2T
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B
12MV2T2
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C
MV2T2
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D
12MV2T
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Solution
The correct option is D12MV2T Power delivered in time T is P=WT
where W is the work done in time T
According to the work energy theorem W=ΔK W=12MV2−0
where V is the final velocity of the particle.
Hence P=12MV2T