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Question

A particle of mass 'm' strikes a smooth stationary wedge of mass M with a velocity v0, at an angle θ with horizontal if the collision is perfectly inelastic, the impulse on the wedge is:
760866_972464698a204a66a0218dbd3e7c86ca.png

A
Mmv0M+m
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B
Mv0
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C
Mmv0cosθM+m
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D
Mmv0sinθM+m
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Solution

The correct option is C Mmv0cosθM+m
Initial momentum along x axis =mv0cosθ

Final momentum =(M+M)v

v=mv0cosθM+m

Impulse = Change in momentum
=Mmv0cosθM+m

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