A particle of small mass $m$ is joined to a very heavy body by a light string passing over a light pulley. Both bodies are free to move. The total downward force on it due to string is near:

m g

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2 m g

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4 m g

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can not be determined

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Solution

The correct option is C $4 m g$
The heavy body will fall due to acceleration due to gravity.The acceleration of the lighter body will be 'g' in upward direction.Taking the equilibrium of the small body
T-mg=ma
but a=g
Therefore, T-mg=mg
T=2mg
Total reaction at the pulley
2T=4mg
Hence option (c) is correct.

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A particle of small mass m is joined to a very heavy body by a light string passing over a light pulley. Both bodies are free to move. The total downward force on it due to string is near:

The correct option is C 4mgThe heavy body will fall due to acceleration due to gravity.The acceleration of the lighter body will be 'g' in upward direction.Taking the equilibrium of the small body T-mg=mabut a=gTherefore, T-mg=mgT=2mgTotal reaction at the pulley2T=4mgHence option (c) is correct.

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