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Question

A particle of specific charge α starts moving from the origin under the action of an electric field E=E0^i and magnetic field B=B0^k. Its velocity at (x0,y0,0) is (4^i+3^j). The value of x0 is


A

16αB0E0

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B

13αE02B0

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C

252αE0

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D

5α2B0

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Solution

The correct option is C

252αE0


From work-energy theorem, ΔWE+ΔWB=ΔK
qE0x0+0=12mv2=12m(32+42)
qmE0x0=252
αE0x0=252
x0=252αE0


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