A particle originally at rest at the highest point of a smooth vertical circle is slightly displaced. It will leave the circle at a vertical distance $h$ below the highest point such that

h = R

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h = \frac{R}{3}

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h = \frac{R}{2}

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h = \frac{2 R}{3}

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Solution

The correct option is B $h = \frac{R}{3}$
Correct option $h = (\frac{R}{3})$
$x + h = R$
$x = (\frac{2 R}{3})$

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