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Question

A particle P moves along a straight line away from a fixed point O obeying the relation S=16+48tt3. The direction of P after t=4 is

A
PO
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B
OP
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C
Rest at the instant
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D
Perpendicular to OP
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Solution

The correct option is A PO
Displacement is given by S(t)=16+48tt3
V=dSdt=483t2
Clearly, for t>4,V<0
Negative sign indicates that it is moving towards the origin.

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