A particle performing circular motion has an angular displacement of 90 degrees. What is its corresponding linear displacement. The radius of the circle described is 10 cms

10 \sqrt{2}

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10 \sqrt{3}

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Solution

The correct option is A $10 \sqrt{2}$
Linear displacement $= A B$
$= \sqrt{10^{2} + 10^{2}} = \sqrt{100 + 100} = \sqrt{200} = 10 \sqrt{2} c m$

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A particle performing circular motion has an angular displacement of 90 degrees. What is its corresponding linear displacement. The radius of the circle described is 10 cms

The correct option is A 10√2Linear displacement =AB=√102+102=√100+100=√200=10√2cm

The correct option is A $10 \sqrt{2}$
Linear displacement $= A B$
$= \sqrt{10^{2} + 10^{2}} = \sqrt{100 + 100} = \sqrt{200} = 10 \sqrt{2} c m$