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Byju's Answer
Standard XII
Physics
Simple Harmonic Oscillation
A particle pe...
Question
A particle performing linear simple harmonic motion has maximum velocity
25
c
m
/
s
and maximum acceleration of
100
c
m
/
s
2
. Find the amplitude and period of oscillation.
(
π
=
3.142
)
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Solution
Given:-
V
M
A
X
=
25
c
m
/
s
2
a
m
a
x
=
100
c
m
/
s
2
A
=
?
and
T
=
?
V
M
A
X
=
ω
A
and
a
m
a
x
=
ω
2
A
ω
=
a
m
a
x
V
M
A
X
=
100
25
=
4
T
=
2
π
ω
=
44
7
×
4
=
11
7
=
1.57
s
e
c
A
=
V
M
A
X
ω
=
25
4
=
6.25
c
m
s
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