A particle performing SHM has a velocity v0 at mean position. Find the velocity of the particle, when it reaches a point which is at a distance A2 from the mean position.
[A= amplitude of SHM]
A
v04
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B
√32v0
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C
3v02
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D
v0√2
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Solution
The correct option is B√32v0 Velocity-displacement relationship for SHM is v=ω√A2−x2
At mean point, x=0&v=ωA=v0
When the particle is at x=A2, v=ω√A2−(A2)2=ω√3A24 ⇒v=√3Aω2⇒v=√3v02