Question

A particle performs SHM on a straight line with time period $T$ and amplitude $A.$ The average speed of the particle between two successive instants, when potential energy and kinetic energy become same is

• A. $\frac{A}{T}$
• B. $\frac{4\sqrt{2}A}{T}$
• C. $\frac{2A}{T}$
• D. $\frac{2\sqrt{2}A}{T}$

Answer 1

The correct option is B $\frac{4\sqrt{2}A}{T}$

$\frac{1}{2}k{X}^2=\frac{1}{2}k(A^2-X^2)$
$\therefore$ $X=\pm \frac{A}{\sqrt{2}}$
Average speed$=\frac{d}{t}=\frac{\sqrt{2}A}{T/8+T/8}=\frac{4\sqrt{2}A}{T}$