Question

A particle projected from a tower shown in figure then the distance from the of the foot tower where it Will strike the ground will be (take g = 10 m / $\left(s^2\right)$

• A. $4000/3m$
• B. $5000/3m$
• C. $2000m$
• D. $3000m$

Answer 1

The correct option is A $4000/3m$

$-1500=-100t-\frac{1}{2}\times 10t^2$

$\frac{t^2}{2}+10t-150=0$

$\Rightarrow t=\frac{\left(-2\pm 40\right)}{2}$

So$,$ $t=10sec$ $i.e.,$ horizontal distance

$=\frac{500}{3}\times \frac{4}{3}\times 10=\frac{4000}{3}m$

Hence,

option $\left(A\right)$ is correct answer.