A particle revolves around a circle with an uniform angular velocity of 3 radians/sec. What is the angular displacement of the particle in 6 secs. Express it in degrees

1031.8

degrees

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360

degrees

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131.8

degrees

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101.4

degrees

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Solution

The correct option is A $1031.8$ degrees
Angular displacement = $ω t = 18$ radians
We know that $π$ radians = 180 degrees.
Hence 18 radians = $\frac{180}{π} . (18) = 1031$ degrees
Hence the correct option is (a)

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A particle revolves around a circle with an uniform angular velocity of 3 radians/sec. What is the angular displacement of the particle in 6 secs. Express it in degrees

The correct option is A 1031.8 degreesAngular displacement = ωt=18 radiansWe know that π radians = 180 degrees. Hence 18 radians = 180π.(18)=1031 degreesHence the correct option is (a)

The correct option is A $1031.8$ degrees
Angular displacement = $ω t = 18$ radians
We know that $π$ radians = 180 degrees.
Hence 18 radians = $\frac{180}{π} . (18) = 1031$ degrees
Hence the correct option is (a)