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Question

A particle revolves around a circle with an uniform angular velocity of 3 radians/sec. What is the angular displacement of the particle in 6 secs. Express it in degrees

A
1031.8 degrees
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B
360 degrees
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C
131.8 degrees
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D
101.4 degrees
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Solution

The correct option is A 1031.8 degrees
Angular displacement = ωt=18 radians
We know that π radians = 180 degrees.
Hence 18 radians = 180π.(18)=1031 degrees
Hence the correct option is (a)

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