wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle revolves in clockwise direction (as seen from point A) in a circle C of radius 1 cm and completes one revolution in 2 sec. The axis of the circle and the principal axis of the mirror M coincide, call it AB. The radius of curvature of the mirror is 20 cm. Then, the direction of revolution (as seen from A) of the image of the particle and its speed is

A
clockwise, 1.57 cms1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
clockwise, 3.14 cms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
anticlockwise, 1.57 cms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
anticlockwise, 3.14 cms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A clockwise, 1.57 cms1
By mirror formula: 1v+110=110
v=+5 cm
m=+12
The image revolves in a circle of radius 12 cm. Image of a radius is erect image will revolve in the same direction as the particle. The image will complete one revolution in the same time 2 s.
Velocity of image v is
ωr=2π2×12=π2 cms1=1.57 cms1
Why this question?

Tip: The one common thing for object and image motion is time- so time period for both is same.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Moving Object & Mirror
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon