A particle's motion is given by s=a(t+b(e(−tb)−1)), where (s is in metre, a and b are constants and t is in sec). What will be the instantaneous speed of the particle at t=∞
A
a
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B
b
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C
∞
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D
0
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Solution
The correct option is Aa As we know that instantneous speed =dsdt=d(a(t+b(e−tb−1)))dt⇒v=adtdt+abd(e−tb−1)dt⇒v=a(1−e−tb)
Putting the value of t=∞, in the equation we get v=a