Question

A particle, situated in an object, moves with angular acceleration of $6rad/se{c}^2$ and with $2\sqrt{2}rad/sec$ angular velocity. If the radius of the circular path is $1m$, its total acceleration in $m/se{c}^2$ will be:

• A. $1$
• B. $100$
• C. $10$
• D. $\sqrt{10}$

Answer 1

The correct option is C $10$

Acceleration due to rotation $=V^2/R$

$\frac{(2\sqrt{2}{)}^2}{\left(1\right)}=8$

$\therefore$ Total Acceleartion $=\sqrt{(8{)}^2+(6{)}^2}=\sqrt{64+36}=\sqrt{100}=10$