A particle start moving along a straight line path with a velocity 10ms−1. After 5s, the distance of the particle from the starting point is 50m. Which of the following statement about the nature of motion of the particle are correct?
A
The body may be speeding up with constant positive acceleration.
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B
The motion may be moving with constant velocity.
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C
The body may have constant negative acceleration.
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D
The motion may be first acceleration and then retarded.
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Solution
The correct options are B The motion may be moving with constant velocity. C The body may have constant negative acceleration. D The motion may be first acceleration and then retarded.
→ If Pt B moving with constant velocity,
S=ut+12at2
=10×5
=50m
→ If the final position Ps 50m behind its initial position,
S=ut+12at2
−50=10×5+12a×25
⇒a=−8
∴ constant retardation.
→ A combination of acceleration and retardation can also satisfy the given condition.