Question

A particle start moving from rest state along a straight line under the action of a constant force and level distance $x$ first $5seconds$. The distance traveled by it in next five second will be:

• A. $x$
• B. $2x$
• C. $3x$
• D. $4x$

Answer 1

The correct option is C $3x$

we know distance covered in straight line is given as $S=ut+a{t}^2/2$

for starting from rest take initial velocity $u=0$ we get $S=a{t}^2/2$

It is given that for $t=5second$ $S=x$ so $x=a{5}^2/2=25a/2$

Now distance in the duration of 6 to 10 second will be distance in 10 second - distance in 5 seconds $=a{10}^2/2-a{5}^2/2=75a/2=3\times 25a/2=3x$.

Answer is $3x$