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Standard IX

Physics

Conditions for Equation of Motion

A particle st...

Question

A particle starting from rest and moving with uniform acceleration along a straight line covers distance a and b in successive intervals of p and q second. The acceleration of particle is ?

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Solution

Dear Student,

$U \sin g n e w t o n' s e q u a t i o n a s s u m e t h a t a c c e l e r a t i o n i s x a = \frac{1}{2} x p^{2} a + b = \frac{1}{2} x {(p + q)}^{2} s u b t r a c t t h e s e e q u a t i o n b = \frac{1}{2} x (p^{2} + q^{2} + 2 p q - p^{2}) x = \frac{2 b}{q^{2} + 2 p q}$

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A particle starting from rest and moving with uniform acceleration along a straight line covers distance a and b in successive intervals of p and q second. The acceleration of particle is ?

Dear Student, Using newton's equation assume that acceleration is xa = 12xp2a+b = 12xp+q2subtract these equationb = 12x(p2+q2+2pq-p2)x = 2bq2+2pq

Dear Student,

$U \sin g n e w t o n' s e q u a t i o n a s s u m e t h a t a c c e l e r a t i o n i s x a = \frac{1}{2} x p^{2} a + b = \frac{1}{2} x {(p + q)}^{2} s u b t r a c t t h e s e e q u a t i o n b = \frac{1}{2} x (p^{2} + q^{2} + 2 p q - p^{2}) x = \frac{2 b}{q^{2} + 2 p q}$