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Question

A particle starting from rest undergoes a rectilinear motion with acceleration a. The variation of a with time is shown below. The maximum velocity attained by the particle during its motion is
1089541_7d0da0770525459cace54019bf791652.jpg

A
120 m/s
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B
60 m/s
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C
22 m/s
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D
80 m/s
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Solution

The correct option is B 60 m/s
area under avst graph gives the change in velocity.
So from give figure (graph) the change in velocity v= area =12×base×height
v=12×(12sec)10m/s2
v=60m/s
as it stated from rest so after 12 sec the velocity will be max=0+v=60m/s
after t=12 sec the acceleration will become zero
So No more change in velocity.



































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